
Let us understand some other features of a parabola.
(a) Focal Distance:
The distance of a point on the parabola from its focus is called the focal distance of the point Focal distance of P = SP = x + a.
(b) Focal Chord:
A chord of the parabola, which passes through its focus, is called Focal chord.
(c) Latus Rectum:
The chord through focus and perpendicular to the axis of the parabola is called the latus rectum.
The co-ordinates of the end point of the latus rectum are (a, 2a) and (a, –2a) and length of latus rectum = 4a.
For horizontal parabola
Let us consider origin (0, 0) as the vertex A of the parabola and two equidistant points S(a, 0) as focus and Z(–a, 0) a point on the directrix now let P(x, y) be the moving point. Draw SZ perpendicular from S on the directrix. Then SZ is the axis of the parabola. Now the middle point of SZ, that is A, will lie on the locus of P.
i.e. AS = AZ
The x-axis along AS, and the y-axis along the perpendicular to AS, as A, as in the figure. Now by definition PM = PS ⇒ MP2 = PS2
So, that, (a + x)2 = (x – a)2 + y2.
Hence, the equation of horizontal parabola is y2 = 4ax.
Similarly for the vertical parabola
Let us consider origin (0, 0) as the vertex A of the parabola and two equidistant points S(0, b) as focus and Z(0, –b) a point on the directrix now let P(x, y) be the moving point. Draw SZ perpendicular from S on the directrix. Then SZ is the axis of the parabola. Now the middle point of SZ, that is A, will lie on the locus of P i.e. AS = AZ.
The y-axis along AS, and the x-axis along the perpendicular to AS at A, as in the figure.

Now by definition PM = PS
⇒ MP2 = PS2
So that, (b + y)2 = (y – b)2 + x2.
Hence, the equation of vertical parabola is x2 = 4by.
Finding the end points of latus Rectum
For finding the end points of latus rectum LL’ of the parabola y2 = 4ax, we put x = a as latus rectum passes through focus (a, 0) therefore we have
So, that, (a + x)2 = (x – a)2 + y2.
Hence, the equation of horizontal parabola is y2 = 4ax.
Similarly for the vertical parabola
Let us consider origin (0, 0) as the vertex A of the parabola and two equidistant points S(0, b) as focus and Z(0, –b) a point on the directrix now let P(x, y) be the moving point. Draw SZ perpendicular from S on the directrix. Then SZ is the axis of the parabola. Now the middle point of SZ, that is A, will lie on the locus of P i.e. AS = AZ.
The y-axis along AS, and the x-axis along the perpendicular to AS at A, as in the figure.

Now by definition PM = PS
⇒ MP2 = PS2
So that, (b + y)2 = (y – b)2 + x2.
Hence, the equation of vertical parabola is x2 = 4by.
Finding the end points of latus Rectum
For finding the end points of latus rectum LL’ of the parabola y2 = 4ax, we put x = a as latus rectum passes through focus (a, 0) therefore we have

y2 = 4a2
⇒ y = + 2a
Hence the end points are (a, 2a) and (a, – 2a).
Also LSL’ = 2a – (–2a) = 4a = length of double ordinate through the focus S.
Note:
Two parabolas are said to be equal when their latus recta are equal.
The important points & lines related to standard Parabola
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